PawSteps · Pets on the Green
Bite-sized lesson

GCSE Maths — Ratio, Proportion & Rates of Change

GCSE Maths · Ages 14–16

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Taught through feeding, dosing and running costs

Approx. 60 minutes · KS4 · Foundation and Higher content flagged separately

Before you start

Every number in this lesson is the kind a keeper actually works out, usually standing up, usually before doing something that matters. Get a ratio wrong when mixing a disinfectant and you either fail to kill anything or burn an animal's feet.

Nothing here is timed. There is no score. You can look at any answer whenever you like — that is not cheating, it is how anyone learns a method.

What you'll be able to do by the end

Part 1 — Ratio in the real setting

Dividing a quantity in a ratio

A dry food mix is made in the ratio 5 : 3 : 2 — insect protein to fruit to supplement. You want to make 2 kg.

Total parts: 5 + 3 + 2 = 10 One part: 2000 g ÷ 10 = 200 g Insect protein: 5 × 200 = 1000 g Fruit: 3 × 200 = 600 g Supplement: 2 × 200 = 400 g

Check: 1000 + 600 + 400 = 2000 g. Always check. It takes four seconds and catches most errors.

Working backwards from one part

Same 5 : 3 : 2 mix. You have exactly 750 g of fruit and want to use all of it.

Fruit is 3 parts, so one part = 750 ÷ 3 = 250 g.

Insect protein: 5 × 250 = 1250 g Supplement: 2 × 250 = 500 g Total mix: 10 × 250 = 2500 g
The step people skip Find the value of one part first, every time. Nearly every ratio error comes from dividing by the wrong number — usually by one of the ratio numbers instead of by the total, or by the total when the question gave you a single part.

Check yourself

A disinfectant is diluted 1 : 49 with water — one part concentrate to forty-nine parts water. You need 5 litres of solution.

How much concentrate?

Answer
Total parts = 1 + 49 = 50 One part = 5000 ml ÷ 50 = 100 ml Concentrate = 1 × 100 = 100 ml, with 4900 ml of water.

The common wrong answer is 5000 ÷ 49. Note that "1 : 49" means one part in fifty, not one part in forty-nine.

Part 2 — Direct and inverse proportion

Direct proportion: as one goes up, the other goes up by the same factor. Double one, double the other. y = kx.

Inverse proportion: as one goes up, the other goes down by the same factor. Double one, halve the other. y = k / x.

The exam tests whether you can tell which is which. The animal room gives clean examples of both.

Direct. Food required and number of animals. Twenty hedgehogs eat twice what ten hedgehogs eat.

Inverse. Food supply and how long it lasts. A sack that feeds ten hedgehogs for twelve days feeds twenty for six.

Worked example — direct

Twelve hedgehogs eat 900 g of food per day. How much do 20 eat?

Per hedgehog: 900 ÷ 12 = 75 g 20 hedgehogs: 75 × 20 = 1500 g

Worked example — inverse

A sack of food lasts 12 hedgehogs 15 days. How long for 20?

Total hedgehog-days: 12 × 15 = 180 For 20 hedgehogs: 180 ÷ 20 = 9 days
How to tell them apart Ask: if I add more animals, does this number get bigger or smaller? More animals, more food per day — direct. More animals, fewer days the sack lasts — inverse. The sentence answers it faster than a formula.

Check yourself

Three misting nozzles fill a reservoir in 40 minutes. How long would five nozzles take, assuming they work at the same rate?

Answer
Inverse proportion — more nozzles, less time. Total nozzle-minutes = 3 × 40 = 120 With 5 nozzles: 120 ÷ 5 = 24 minutes

Part 3 — Units, concentration and dosing

This is where marks are lost to arithmetic rather than method, and where a real error does real harm.

Mass: 1 kg = 1000 g. 1 g = 1000 mg.
Volume: 1 litre = 1000 ml.
Concentration: mg per ml, or g per litre. They are the same relationship at different scales.

Worked example — dosing by body mass

A medication is given at 5 mg per kg of body mass. The animal weighs 380 g. The solution is 10 mg per ml.

Convert mass: 380 g = 0.38 kg Dose required: 5 × 0.38 = 1.9 mg Volume to give: 1.9 ÷ 10 = 0.19 ml

Three conversions, three chances to be out by a factor of ten. Write the units next to every number as you go — that alone catches most of these.

Why this is on the paper and in the room Dosing by body mass is standard veterinary practice and it is standard GCSE compound-measures content. The maths is identical. The difference is that in the room, an error of one decimal place is a tenfold overdose.

This lesson teaches the arithmetic. It is not veterinary guidance, and medication should only ever be given on a vet's instruction.

Check yourself

A supplement is dosed at 2 mg per kg. The animal weighs 1.4 kg. The solution supplies 4 mg per ml. What volume is given?

Answer
Dose = 2 × 1.4 = 2.8 mg Volume = 2.8 ÷ 4 = 0.7 ml

Part 4 — Percentages and rates of change

Percentage change

percentage change = (change ÷ original) × 100

A hoglet weighs 62 g on Monday and 74 g the following Monday.

Change = 74 − 62 = 12 g Percentage change = (12 ÷ 62) × 100 = 19.4% (1 d.p.)

Reverse percentages — the one people get wrong

Feed costs rose by 12% and a sack now costs £28. What did it cost before?

The wrong method is subtracting 12% of £28. That gives £24.64, which is wrong.

The right method: £28 represents 112% of the original.

1% = 28 ÷ 112 = 0.25 100% = 0.25 × 100 = £25.00

Check: £25 × 1.12 = £28. Correct.

Rate of change

A tortoise gains mass at roughly 40 g per month.

In a year: 40 × 12 = 480 g To gain 1 kg: 1000 ÷ 40 = 25 months

Rates are just division with units attached. Keep the units visible and the method is obvious.

Check yourself

Electricity for the heating cost £180 last quarter and £207 this quarter. Calculate the percentage increase.

Answer
Change = 207 − 180 = £27 (27 ÷ 180) × 100 = 15%

Part 5 — Exam-style questions

1. A food mix is made in the ratio 7 : 4 : 1. A batch contains 240 g of the middle ingredient. Calculate the total mass of the batch. (3 marks)

Mark scheme
1 mark: one part = 240 ÷ 4 = 60 g 1 mark: total parts = 12 1 mark: total mass = 12 × 60 = 720 g

2. A disinfectant is diluted 1 : 24 with water. Calculate the volume of concentrate needed to make 3 litres of solution. (3 marks)

Mark scheme
1 mark: total parts = 25 1 mark: one part = 3000 ÷ 25 = 120 ml 1 mark: concentrate = 120 ml

3. Eight animals consume a sack of food in 21 days. Assuming the same rate per animal, calculate how long the same sack would last 14 animals. (3 marks)

Mark scheme
1 mark: recognises inverse proportion. 1 mark: total animal-days = 8 × 21 = 168 1 mark: 168 ÷ 14 = 12 days

4. A medication is given at 8 mg per kg of body mass. An animal weighs 450 g. The solution contains 20 mg per ml. Calculate the volume to be given, in ml. (4 marks)

Mark scheme
1 mark: 450 g = 0.45 kg 1 mark: dose = 8 × 0.45 = 3.6 mg 1 mark: volume = 3.6 ÷ 20 1 mark: = 0.18 ml

Allow error carried forward.

5. After a 15% increase, a sack of food costs £36.80. Calculate the price before the increase. (3 marks)

Mark scheme
1 mark: recognises £36.80 as 115% of the original. 1 mark: 36.80 ÷ 115 = 0.32, or equivalent division by 1.15 1 mark: original = £32.00

No marks for subtracting 15% of £36.80.

6. (Higher) The mass of a growing animal is directly proportional to the square root of its age in weeks. At 16 weeks it has a mass of 240 g. Calculate its mass at 25 weeks. (4 marks)

Mark scheme
1 mark: writes m = k√t 1 mark: 240 = k√16 = 4k, so k = 60 1 mark: m = 60 × √25 = 60 × 5 1 mark: = 300 g

If you want to go further

Notes for the adult

Curriculum: GCSE Maths — ratio and proportion, compound measures, percentage change and reverse percentages, and rates of change. Question 6 is Higher tier only and is flagged as such; everything else is accessible at Foundation.

The misconceptions this lesson targets: reading "1 : 49" as one in forty-nine, and reversing a percentage by subtracting it. Both are addressed explicitly with the wrong answer shown alongside the right one, because students who have made the error need to see it named.

On the dosing section. The arithmetic is standard compound-measures content and the veterinary framing is what makes it stick. The lesson states plainly that it is not veterinary guidance. If you are working with a student who might take it as such, say so aloud as well.

For a student who finds this hard. Parts 1 and 4 stand alone as a shorter session on ratio and percentages, without proportion or dosing. That is a complete and useful piece of maths on its own.

Access: read-aloud, dyslexia-friendly font, enlarged text, high contrast and calm mode on every page. Worked examples are laid out one step per line rather than as continuous prose.

No timing, no scoring. Nothing here is marked, logged or reported. Answers are available immediately by design.

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