76mark paper
PawSteps · Pets on the Green

GCSE Physics — Energy, Forces and Motion

A full teaching unit — energy stores and transfers, the energy equations, forces, Newton's laws, motion, stopping distance and momentum — taught the way marks are actually won: on method and units, not just physics. With worked calculations, free-body reasoning, a mark scheme and a 76-mark exam paper.

AQA 4.1 and 4.5 · Edexcel Topics 2 and 3 · OCR P1 and P2 · WJEC Unit 1 · ~15–18 hours · Prior knowledge: units and measurement, rearranging simple formulae

What you'll be able to do by the end

  1. Describe the energy stores and the ways energy is transferred
  2. Apply conservation of energy and calculate efficiency
  3. Calculate kinetic, gravitational potential and elastic potential energy
  4. Calculate power and work done
  5. Draw and interpret free body diagrams and calculate resultant forces
  6. Use the equations of motion
  7. Interpret distance–time and velocity–time graphs
  8. Apply Newton's three laws
  9. Calculate momentum and apply conservation of momentum
  10. Explain stopping distance and the factors affecting it
💡 Physics is the subject where students fail on maths, not on physics

Most lost marks in this topic are unit errors, unconverted values and rearranged equations — not misunderstandings. Teach the method as hard as the content.

The teaching below is free to read and print. The exam questions, mark scheme and teaching notes are PawSteps Premium.

Part 1 — Working with equations

Before any content — this is the part that costs the marks.

The method that gets full marks

StepWhat to do
1. Write the equationEven if you rearrange it later. It's often worth a mark on its own
2. Convert unitsEverything into SI units before substituting
3. SubstituteNumbers in, showing your working
4. Calculate
5. UnitsEvery answer needs them
💡 Why writing the equation first matters

If you get the arithmetic wrong but wrote the correct equation and substituted correctly, you usually get 2 out of 3.

If you write only an answer and it's wrong, you get 0.

Never do it in your head.

Units you must convert

GivenConvert toHow
GramsKilograms÷ 1000
KilometresMetres× 1000
MinutesSeconds× 60
HoursSeconds× 3600
km/hm/s÷ 3.6
CentimetresMetres÷ 100
KilojoulesJoules× 1000
⚠️ The error that costs most marks in GCSE Physics

Not converting grams to kilograms.

A 500 g mass is 0.5 kg. Using 500 makes every answer 1000 times too large.

Check every mass before you substitute. If your answer for the kinetic energy of a tennis ball comes out as 40,000 J, you've done it.

Part 2 — Energy

The energy stores

Energy is not created or destroyed — it is transferred between stores.

StoreExample
KineticAnything moving
Gravitational potentialAnything raised above the ground
Elastic potentialA stretched spring or elastic band
Thermal (internal)A hot object
ChemicalFood, fuel, a battery
NuclearThe nucleus of an atom
MagneticTwo magnets held apart
ElectrostaticTwo charges held apart

Ways energy is transferred

PathwayExample
MechanicallyBy a force doing work — pushing, lifting
ElectricallyBy a current
By heatingConduction, convection
By radiationLight, sound, infrared
⚠️ Stores and pathways are different things

"Light energy" and "sound energy" are not stores. They are pathways — ways energy moves.

Modern specifications are strict about this. Write "energy is transferred by radiation" or "energy is transferred to the thermal store of the surroundings."

Conservation of energy

Energy cannot be created or destroyed. It can only be transferred, stored or dissipated.

Dissipated means spread out into the surroundings, usually to the thermal store — where it is no longer useful.

Efficiency

Efficiency = (useful energy transferred ÷ total energy supplied) × 100%

Worked example. A motor is supplied with 500 J and usefully transfers 350 J to the kinetic store.

(350 ÷ 500) × 100 = 70% efficient

The other 150 J is dissipated, usually as heat and sound.

No device is 100% efficient. Some energy is always dissipated.

Reducing unwanted transfers

MethodWhere
LubricationReduces friction between moving parts
InsulationReduces energy transfer by conduction
StreamliningReduces air resistance
Cavity wall insulationReduces conduction and convection in buildings

Part 3 — Energy calculations

Kinetic energy

Eₖ = ½ × m × v² Eₖ = kinetic energy (J) m = mass (kg) v = speed (m/s)
A 1200 kg car travels at 15 m/s. Calculate its kinetic energy.
Eₖ = ½ × 1200 × 15² = ½ × 1200 × 225 = 135,000 J (135 kJ)
⚠️ Square the speed, not the whole thing

½ × m × v² means square v first, then multiply.

½ × 1200 × 15 = 9000 ✗ ½ × 1200 × 225 = 135,000 ✓

And note: doubling the speed quadruples the kinetic energy. That's why speed matters so much in crashes.

Gravitational potential energy

Eₚ = m × g × h Eₚ = GPE (J) m = mass (kg) g = gravitational field strength (9.8 N/kg on Earth) h = height (m)
A 65 kg person climbs 12 m of stairs. Calculate the gain in GPE.

Eₚ = 65 × 9.8 × 12 = 7644 J

Elastic potential energy

Eₑ = ½ × k × e² k = spring constant (N/m) e = extension (m)
A spring with spring constant 40 N/m is extended by 0.15 m.

Eₑ = ½ × 40 × 0.15² = ½ × 40 × 0.0225 = 0.45 J

Work done

W = F × d W = work done (J) F = force (N) d = distance moved in the direction of the force (m)

One joule is the work done when a force of one newton moves an object one metre.

A force of 250 N pushes a crate 8 m.

W = 250 × 8 = 2000 J

Power

P = E ÷ t or P = W ÷ t P = power (W) E = energy transferred (J) t = time (s)

Power is the rate of energy transfer. One watt is one joule per second.

A motor transfers 6000 J in 20 seconds.

P = 6000 ÷ 20 = 300 W

💡 What power actually means

Two people carry the same load up the same stairs. They do the same work and transfer the same energy.

The one who does it faster has more power.

Power is not "how much" — it's "how fast."

Part 4 — Forces

Scalars and vectors

HasExamples
ScalarMagnitude onlyDistance, speed, mass, energy, time
VectorMagnitude and directionDisplacement, velocity, force, acceleration, momentum
The pairs that catch people out

Distance is scalar. Displacement is vector.
Speed is scalar. Velocity is vector.
Mass is scalar. Weight is vector — it's a force.

A runner completing a 400 m lap has travelled a distance of 400 m and a displacement of zero.

Contact and non-contact forces

ContactNon-contact
FrictionGravitational
Air resistanceElectrostatic
TensionMagnetic
Normal contact force

Weight

W = m × g W = weight (N) m = mass (kg) g = gravitational field strength (N/kg)

Mass is the amount of matter — kilograms, same everywhere.
Weight is the force of gravity on that mass — newtons, changes with location.

A 70 kg person on Earth (g = 9.8): weight = 686 N. The same person on the Moon (g = 1.6): weight = 112 N. Same mass. Different weight.

Resultant force

The single force that has the same effect as all the forces acting.

Forces in the same direction: add Forces in opposite directions: subtract
A car has 4000 N driving force forwards and 1500 N of resistive forces.

Resultant = 4000 − 1500 = 2500 N forwards

If the resultant force is zero, the object is in equilibrium — either stationary or moving at constant velocity.

Part 5 — Newton's laws

First law

An object will remain at rest, or moving at constant velocity, unless acted on by a resultant force.

Why a car at constant speed still needs its engine

Because the driving force is balancing friction and air resistance, not accelerating the car.

Zero resultant force does not mean no forces. It means they cancel.

Second law

F = m × a F = resultant force (N) m = mass (kg) a = acceleration (m/s²)
A resultant force of 900 N acts on a 600 kg vehicle.

a = F ÷ m = 900 ÷ 600 = 1.5 m/s²

Inertial mass is a measure of how difficult it is to change an object's velocity — the ratio of force to acceleration.

Third law

Whenever two objects interact, the forces they exert on each other are equal and opposite.

You push on the ground; the ground pushes back on you. A book rests on a table; the table pushes up on the book with equal force.
⚠️ Why the pair don't cancel out

The two forces in a Newton's third law pair act on different objects.

You push the ground, the ground pushes you. Only one of those acts on you, so you move.

Forces only cancel when they act on the same object.

Part 6 — Motion

Speed, velocity and acceleration

speed = distance ÷ time acceleration = change in velocity ÷ time a = (v − u) ÷ t u = initial velocity v = final velocity a = acceleration (m/s²)
A car accelerates from 8 m/s to 24 m/s in 4 seconds.

a = (24 − 8) ÷ 4 = 16 ÷ 4 = 4 m/s²

The equation without time

v² − u² = 2 × a × s s = distance (m)
A car accelerates from rest at 3 m/s² over 50 m. Find its final velocity.

v² − 0² = 2 × 3 × 50 = 300 v = √300 = 17.3 m/s

Typical values worth knowing

Speed
Walking~1.5 m/s
Running~3 m/s
Cycling~6 m/s
Car in a town~13 m/s (30 mph)
Sound in air~330 m/s

Distance–time graphs

FeatureMeaning
GradientSpeed
Horizontal lineStationary
Straight sloped lineConstant speed
Curved line getting steeperAccelerating
Curved line getting shallowerDecelerating

To find speed at a point on a curve: draw a tangent and find its gradient.

Velocity–time graphs

FeatureMeaning
GradientAcceleration
Horizontal lineConstant velocity
Straight sloped lineConstant acceleration
Line sloping downDeceleration
Area under the graphDistance travelled
⚠️ The graph confusion

On a distance–time graph, the gradient is speed.

On a velocity–time graph, the gradient is acceleration and the area is distance.

Students routinely find the area under a distance–time graph, which means nothing at all. Check which graph you're looking at first.

Terminal velocity

A falling object:

  1. Initially, weight is greater than air resistance → resultant force downwards → it accelerates
  2. As speed increases, air resistance increases
  3. Eventually air resistance equals weight → resultant force is zero
  4. The object falls at constant terminal velocity

Opening a parachute increases air resistance sharply, so the resultant force is now upwards, the object decelerates, air resistance falls again, and a new lower terminal velocity is reached.

Part 7 — Stopping distance

Stopping distance = thinking distance + braking distance
DistanceWhat it isAffected by
ThinkingDistance travelled during reaction timeTiredness · alcohol · drugs · distractions · speed
BrakingDistance travelled while brakingSpeed · road conditions (wet, icy) · tyre condition · brake condition · vehicle mass
💡 Why speed appears in both columns

Speed affects thinking distance proportionally — twice the speed, twice as far during your reaction time.

Speed affects braking distance as a square — because kinetic energy depends on v². Twice the speed means four times the braking distance.

This is why speed limits matter more than people think, and it's a favourite exam question.

Braking and energy

When brakes are applied, work is done by friction between the brakes and the wheels. The kinetic store of the vehicle is transferred to the thermal store of the brakes, which get hot.

Greater speed requires greater braking force for the same braking distance — which risks brakes overheating and loss of control.

Part 8 — Momentum

p = m × v p = momentum (kg m/s) m = mass (kg) v = velocity (m/s)

Momentum is a vector — direction matters.

Conservation of momentum

In a closed system, the total momentum before an event equals the total momentum after.

A 2 kg trolley moving at 3 m/s collides with a stationary 1 kg trolley. They join together. Find their combined velocity.
Before: (2 × 3) + (1 × 0) = 6 kg m/s After: total mass 3 kg, velocity v 3v = 6 v = 2 m/s

Force and momentum

F = (mv − mu) ÷ t Force = change in momentum ÷ time
Why safety features work

Increasing the time over which momentum changes reduces the force.

FeatureHow it works
Air bagIncreases the time for the body to stop
Crumple zoneDeforms, extending the collision time
Seat beltStretches slightly, increasing stopping time
Crash matCompresses, extending the time
Bending your knees when landingIncreases the time to stop

Same change in momentum. Longer time. Smaller force. That's the whole principle, and it answers every safety-feature question on the paper.

Exam-style questions

Answer all questions. Marks are shown in brackets. Total: 76 marks.

Question 1

(a) Name three energy stores. (3)
Answer

A lamp is supplied with 60 J of energy each second and usefully transfers 9 J as light.

(b)(i) Calculate the efficiency of the lamp. (2)
Working
(b)(ii) State what happens to the rest of the energy. (2)
Answer
(c) Explain why no device can be 100% efficient. (2)
Answer

(Total 9 marks)

Question 2

(a) A 1400 kg car travels at 20 m/s. Calculate its kinetic energy. (3)
Working
(b) The same car travels at 40 m/s. Without calculating, state how its kinetic energy compares, and explain why. (2)
Answer
(c) A 600 g ball is raised 2.5 m. Take g = 9.8 N/kg. Calculate the gain in gravitational potential energy. (3)
Working

(Total 8 marks)

Question 3

A crane lifts a 250 kg load through 15 m in 30 seconds. Take g = 9.8 N/kg.

(a)(i) Calculate the work done. (3)
Working
(a)(ii) Calculate the power of the crane. (2)
Working
(b) Explain the difference between energy and power. (2)
Answer

(Total 7 marks)

Question 4

(a) State the difference between a scalar and a vector quantity, and give one example of each. (3)
Answer

A car has a driving force of 3200 N and experiences resistive forces of 3200 N.

(b)(i) Calculate the resultant force. (1)
Working
(b)(ii) Describe the motion of the car. (2)
Answer
(c) State Newton's first law. (2)
Answer

(Total 8 marks)

Question 5

(a) A resultant force of 1500 N acts on a car of mass 1000 kg. Calculate the acceleration. (3)
Working
(b) A cyclist accelerates from 4 m/s to 10 m/s in 3 seconds. Calculate the acceleration. (3)
Working
(c) A car accelerates from rest at 2.5 m/s² over a distance of 80 m. Calculate its final velocity. (3)
Working

(Total 9 marks)

Question 6

A velocity–time graph shows a vehicle accelerating uniformly from 0 to 20 m/s in 8 seconds, then travelling at a constant 20 m/s for 12 seconds.

(a) Calculate the acceleration in the first 8 seconds. (2)
Working
(b) Calculate the total distance travelled in the 20 seconds. (4)
Working
(c) State what the gradient of a distance–time graph represents. (1)
Answer

(Total 7 marks)

Question 7

(a) Explain, in terms of forces, how a skydiver reaches terminal velocity. (4)
Answer
(b) Describe what happens when the skydiver opens their parachute. (3)
Answer

(Total 7 marks)

Question 8

(a) Define stopping distance. (1)
Answer
(b) Give two factors that increase thinking distance and two that increase braking distance. (4)
Answer
(c) Explain why doubling a car's speed more than doubles its stopping distance. (4)
Answer
(d) Explain, in terms of energy, what happens when a car brakes. (3)
Answer

(Total 12 marks)

Question 9

(a) Calculate the momentum of a 1200 kg car travelling at 15 m/s. (2)
Working
(b) A 3 kg trolley moving at 4 m/s collides with a stationary 1 kg trolley and they move off together. Calculate their combined velocity. (4)
Working
(c) Explain how an air bag reduces injury in a collision. (3)
Answer

(Total 9 marks)

TOTAL FOR PAPER: 76 MARKS

Mark scheme

Question 1

(a) 3 — any three: kinetic · gravitational potential · elastic potential · thermal · chemical · nuclear · magnetic · electrostatic.

(b)(i) 2. (9 ÷ 60) × 1001
= 15%1
(b)(ii) 2. 51 J is dissipated1
to the thermal store of the surroundings1
(c) 2. Some energy is always dissipated to the surroundings1
usually to thermal stores through friction or heating, and is no longer useful1

Question 2

(a) 3. Eₖ = ½ × m × v²1
= ½ × 1400 × 20² = ½ × 1400 × 4001
= 280,000 J (280 kJ)1
(b) 2. It is four times greater1
because kinetic energy is proportional to velocity squared, and doubling v quadruples v²1
(c) 3. 600 g = 0.6 kg1
Eₚ = 0.6 × 9.8 × 2.51
= 14.7 J1

Failing to convert grams gives 14,700 J. Award 1 for method only.

Question 3

(a)(i) 3. Force needed = weight = 250 × 9.8 = 2450 N1
W = F × d = 2450 × 151
= 36,750 J1
(a)(ii) 2. P = 36750 ÷ 301
= 1225 W1
(b) 2. Energy is the total amount transferred, measured in joules1
Power is the rate at which energy is transferred, measured in watts1

Question 4

(a) 3. A scalar has magnitude only1
a vector has magnitude and direction1
any correct examples, e.g. speed is scalar and velocity is vector1

(b)(i) 10 N.

(b)(ii) 2. The car continues at constant velocity1
because with zero resultant force there is no acceleration1
(c) 2. An object remains at rest or moving at constant velocity1
unless acted on by a resultant force1

Question 5

(a) 3. a = F ÷ m1
= 1500 ÷ 10001
= 1.5 m/s²1
(b) 3. a = (v − u) ÷ t1
= (10 − 4) ÷ 31
= 2 m/s²1
(c) 3. v² − u² = 2as1
v² = 2 × 2.5 × 80 = 4001
v = 20 m/s1

Question 6

(a) 2. a = 20 ÷ 81
= 2.5 m/s²1
(b) 4. Distance = area under the graph1
Triangle: ½ × 8 × 20 = 80 m1
Rectangle: 12 × 20 = 240 m1
Total = 320 m1

(c) 1Speed.

Question 7

(a) 4. Initially weight is greater than air resistance, so there is a resultant downward force and the skydiver accelerates1
As speed increases, air resistance increases1
The resultant force decreases, so acceleration decreases1
When air resistance equals weight, the resultant force is zero and the skydiver falls at constant terminal velocity1
(b) 3. Air resistance increases sharply1
Air resistance is now greater than weight, so there is a resultant upward force and the skydiver decelerates1
As speed falls, air resistance falls until it again equals weight, giving a new lower terminal velocity1

Question 8

(a) 1 — thinking distance + braking distance.

(b) 4 — thinking (any two): tiredness · alcohol · drugs · distraction · speed. Braking (any two): speed · wet or icy road · worn tyres · worn brakes · greater mass.

(c) 4. Thinking distance is proportional to speed, so it doubles1
Braking distance depends on kinetic energy1
Kinetic energy is proportional to v², so doubling the speed quadruples it1
Braking distance therefore quadruples, so the total more than doubles1
(d) 3. Work is done by friction between the brakes and the wheels1
Energy is transferred from the kinetic store of the vehicle1
To the thermal store of the brakes, which increase in temperature1

Question 9

(a) 2. p = m × v = 1200 × 151
= 18,000 kg m/s1
(b) 4. Momentum before = (3 × 4) + (1 × 0) = 12 kg m/s1
Momentum is conserved, so momentum after = 12 kg m/s1
Combined mass = 4 kg, so 4v = 121
v = 3 m/s1
(c) 3. The air bag increases the time taken for the passenger's momentum to change to zero1
Force = change in momentum ÷ time1
A longer time means a smaller force acting on the passenger, so less injury1
Common mistakes in this topic

Not converting grams to kilograms. Every answer comes out 1000 times too big. Check every mass.

Not squaring v in kinetic energy. ½mv² means square the velocity first.

Finding the area under a distance–time graph. It means nothing. Area is only meaningful under a velocity–time graph.

Confusing mass and weight. Kilograms and newtons.

Saying "there are no forces" when the resultant is zero. The forces are balanced, not absent.

Saying Newton's third law pairs cancel. They act on different objects.

"Light energy" and "sound energy." These are pathways, not stores.

Omitting units. A number without units is usually not a complete answer.

Teaching notes

Teach the equation method before any content. Write it, convert, substitute, calculate, units. Drilled properly it earns partial credit on every calculation for the rest of the course, and it turns a wrong answer worth 0 into a wrong answer worth 2.

The grams-to-kilograms conversion deserves a starter every lesson for a fortnight. It is the single biggest source of lost marks in GCSE Physics and it is entirely preventable.

v² is the idea that explains stopping distances. Doubling speed quadruples kinetic energy and quadruples braking distance. Students who understand this can answer road-safety questions from first principles instead of memorising a table.

The two graph types must be distinguished explicitly and repeatedly. Gradient of distance–time is speed. Gradient of velocity–time is acceleration, and the area is distance. Ask "which graph am I looking at?" before every question.

Terminal velocity is best taught as a sequence, not a definition. Weight greater → accelerates → air resistance increases → forces balance → constant velocity. Four steps, four marks, and it works for the parachute question too.

All the safety-feature questions have one answer. Increase the time, reduce the force. Air bags, crumple zones, seat belts, crash mats, bending your knees. Teach the principle once and students can answer any version of it.

Written for GCSE Physics, all major UK boards. Check your specification — momentum and the v² − u² = 2as equation are Higher Tier on most boards. Reviewed 2026.

Part of the Post-16 & GCSE resources

Teaching is free · the exam paper & mark scheme are Premium